To find the percentile for the score of 117, we need to determine how many students scored less than 117 out of the total 12 students.
First, let's arrange the scores in ascending order:
98, 101, 117, 121, 122, 127, 130, 137, 138, 143, 145, 152
Now, count the number of scores less than 117:
- Scores less than 117 are: 98, 101
There are 2 scores less than 117.
Next, we can calculate the percentile using the formula:
\[ P = \left(\frac{N_L}{N}\right) \times 100 \]
where:
- \(N_L\) is the number of values less than the score,
- \(N\) is the total number of values.
In this case:
- \(N_L = 2\)
- \(N = 12\)
Now plug in the values:
\[ P = \left(\frac{2}{12}\right) \times 100 \approx 16.67 \]
Thus, the percentile rank for a score of 117 is approximately 16.67, which would round to the 17th percentile.
Therefore, the answer is:
a. 17th percentile