To balance a seesaw, the distance, in feet, a person is from the fulcrum is inversely proportional to the person's weight, in pounds. Peter, who weighs 150 pounds, is sitting 3 feet away from the fulcrum. If Joey weighs 90 pounds, how far from the fulcrum should he sit to balance the seesaw?

Answer 1

d = k/w
if w=150 , d = 3
3 = k/150
k = 450

so d = 450/w

if w = 90
d = 450/90 = 5

or

w1/w2 = d2/d1
150/90 = d2/3
d2 = 3(150/90) = 5

Answer 2

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Answer 3

Rainy is right

Answer 4

thanks

Answer 5

Thank you so much, this helped a lot!