HAc + NaOH ==> NaAc + H2O
First, determine the molarity of the HAc.
mL x M = mL x M
22.5 x 0.21 = 50*x
x = 0.0945M
Now divide the titration curve into four sections.
a. at the beginning.
b. between initial and eq point
c. eq pt
d. after eq pt
Which of these do you have trouble doing? I see no point in repeating those steps you know how to do.
Titration of 50.0 mL of acetic acid reaches equivalence after delivery of 22.5mL of standardized NaOH 0.21 M.
What is the initial concentration of acetic acid and what is the pH of the solution?
What is the pH at equivalence?
What is the pH adition of 20.0 mL of NaOH?
What volume of titrant (NaOH) must be delivered to reach a pH of 4.74?
2 answers
I figured it out. Thank you!
1 answer