Titration of 25.00 mL of KOH required 200.00 mL of 0.0050 M acetic acid, CH3COOH. What is the molarity (M) of the KOH solution? Please show calcutions.

Answer 1

HAc = CH3COOH = acetic acid
KOH = potassium hydroxide
mL KOH x M KOH = mL HAc x M HAc
Substitute and solve for M KOH

Answer 2

0.04