Sn atomic mass = 118.71
Oxygen atomic mass = 16.00
Number of tin atoms = 1
Number of oxygen atoms = 2
Total mass = (118.71*1)+(16.00*2)
= 150.71
(118.71/150.71)*100 = percentage of tin composition in SnO2
((16.00*2))/150.71)*100 = percentage of oxygen composition in SnO2
Tin (Sn) exists in earths crust as SnO2. Calculate the percent composition by mass of Sn and O in SnO2.
Please help me with this question I'm so confused
3 answers
So do they have to be separate percentages or do you add them together
You don't get it??? The calculation gave you the % Sn and the % Oxygen. You don't do anything with them You might notice they add to 100% and they should.
Think about it. If you had 10 lbs oranges and 10 lbs apples in a basket what percentage apples and what percentage oranges do you have?
(10 lbs apples/total of 20 lbs) *100 = 50%
Likewise % Sn = (grams Sn/total grams)*100 = ?
I'll bet you could do the apples/oranges problem in your head. So don't let changing apples to tin and oranges to oxygen make any difference in your thinking skills.
Think about it. If you had 10 lbs oranges and 10 lbs apples in a basket what percentage apples and what percentage oranges do you have?
(10 lbs apples/total of 20 lbs) *100 = 50%
Likewise % Sn = (grams Sn/total grams)*100 = ?
I'll bet you could do the apples/oranges problem in your head. So don't let changing apples to tin and oranges to oxygen make any difference in your thinking skills.
9 answers