Question
                Tickets for a choir concert cost $3 for students and $5 for adults.  The choir director wants to sell at least $1,500 worth of tickets to this concert.  She knows that 226 students purchased a ticket.
Enter the minimum number of adults that need to purchase a ticket to raise at least $1,500.
            
            
        Enter the minimum number of adults that need to purchase a ticket to raise at least $1,500.
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                    Answered by
            GPT-4o mini
            
    To determine the minimum number of adults that need to purchase a ticket, we begin by calculating the total revenue generated by the students.
Given that the cost of a student ticket is $3 and that 226 students purchased tickets, we can calculate the total revenue from student ticket sales as follows:
\[
\text{Revenue from students} = 226 \times 3 = 678 \text{ dollars}
\]
Next, we need to find out how much more money is needed to reach the minimum goal of $1,500. We do this by subtracting the revenue from students from the total target:
\[
\text{Additional revenue needed} = 1500 - 678 = 822 \text{ dollars}
\]
Now, let \( x \) represent the number of adult tickets sold. The price of an adult ticket is $5, so the revenue generated from adult ticket sales can be expressed as:
\[
\text{Revenue from adults} = 5x
\]
We need this revenue from adults to be at least $822:
\[
5x \geq 822
\]
To isolate \( x \), we divide both sides of the inequality by 5:
\[
x \geq \frac{822}{5} = 164.4
\]
Since \( x \) must be a whole number (as you cannot sell a fraction of a ticket), we round up to the nearest whole number:
\[
x \geq 165
\]
Therefore, the minimum number of adults that need to purchase a ticket is \( \boxed{165} \).
    
Given that the cost of a student ticket is $3 and that 226 students purchased tickets, we can calculate the total revenue from student ticket sales as follows:
\[
\text{Revenue from students} = 226 \times 3 = 678 \text{ dollars}
\]
Next, we need to find out how much more money is needed to reach the minimum goal of $1,500. We do this by subtracting the revenue from students from the total target:
\[
\text{Additional revenue needed} = 1500 - 678 = 822 \text{ dollars}
\]
Now, let \( x \) represent the number of adult tickets sold. The price of an adult ticket is $5, so the revenue generated from adult ticket sales can be expressed as:
\[
\text{Revenue from adults} = 5x
\]
We need this revenue from adults to be at least $822:
\[
5x \geq 822
\]
To isolate \( x \), we divide both sides of the inequality by 5:
\[
x \geq \frac{822}{5} = 164.4
\]
Since \( x \) must be a whole number (as you cannot sell a fraction of a ticket), we round up to the nearest whole number:
\[
x \geq 165
\]
Therefore, the minimum number of adults that need to purchase a ticket is \( \boxed{165} \).
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