Let's assign variables to the present ages of the father and son. Let f be the father's age and s be the son's age.
According to the problem, three years ago, the father was three times as old as his son:
f - 3 = 3(s - 3) [Equation 1]
In three years time, the sum of their ages will be 76 years:
(f + 3) + (s + 3) = 76 [Equation 2]
Now, let's solve the system of equations:
Expanding equation 1, we get:
f - 3 = 3s - 9
f - 3s = -6 [Equation 3]
Rearranging equation 2, we get:
f + s = 76 - 6
f + s = 70 [Equation 4]
Using equations 3 and 4, we can solve for f and s.
Multiply equation 3 by -1:
-f + 3s = 6 [Equation 5]
Add equations 4 and 5:
f + s + (-f + 3s) = 70 + 6
4s = 76
s = 19
Substituting the value of s into equation 4:
f + 19 = 70
f = 70 - 19
f = 51
Therefore, the father is currently 51 years old and the son is currently 19 years old.
three years ago, a father was three times as old as his son. In three years time the sum of their aged will be 76 years. Determine their present ages
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