Three vectors are shown in the figure below, but they are not drawn to scale. The sum of the three vectors is R = F1 + F2 + F3. If Ry = 0 and F2 = 0.2F3, find Rx in terms of F1. the Answer Keyis 0.327.can somebody show me how to get to the answer key. I try my best to describe the figure. the figure looks like an x with an exra line draw from the center of the x downward in other word like an upside down star. F1 is that line and on the left of that line is 30degree. F2 point on the north-west side and F3 point on the north-east side. Please help.I'm stuck.
6 answers
I need the figure.
do you know anyway for me to show you the figure on this site bobpursley?I had try copy and pasted but not show up and I can't paste any link on this site either.
bobpursley I just send you an email. check and see did you receive it yet
so Ry is zero, which means cos30*F1=-F3
and F2 = 0.2F3, so
Rx=???F3 is the question
Rx=sin30*F1 from the figure.
Rx=.5F1-F2=.3(-F3/cos30)-.2F3 and you have it.
check my thinking.
and F2 = 0.2F3, so
Rx=???F3 is the question
Rx=sin30*F1 from the figure.
Rx=.5F1-F2=.3(-F3/cos30)-.2F3 and you have it.
check my thinking.
I don't get it what is the value forF1? can you show step by step with number?
Opps, I solve it for Rx in terms of F3, you want it in terms of F1
Rx=F1*sin30-F2
= .5F1-.2F2
but F2=.2F3=.2(-F1*cos30)
Rx=.5F1-.2* cos30 F1
=F1(.5-.2*.866)=.327F1
Rx=F1*sin30-F2
= .5F1-.2F2
but F2=.2F3=.2(-F1*cos30)
Rx=.5F1-.2* cos30 F1
=F1(.5-.2*.866)=.327F1
1 answer