Three towns a, b, and c are such that the distance between a and b is 50km and the distance between a and c is 90km. if the bearing of b from a is 075' and the bearing of c from a is 310'. find the distance between b and c?

6 answers

I will assume you meant ° for degrees.
angles are measured in degrees, subdivided into 60 minutes, and then again into 60 seconds (just like "time" )

e.g. 34° 12' 35" <--- 34 degrees, 12 minutes, and 35 seconds

Make a sketch
From your description, I have a triangle ABC
with angle A = 125° , AB = 50 and AC = 90

using cosine law:
BC^2 = 50^2 + 90^2 - 2(50)(90)cos 125°
= 10600 - 9000(-.57357..)
= ...

finish it up

291

how did u solved it pls

Please how did you solve it and got the bearing as 291

Let me see the working

I want to see the diagram