well 11^3 = 1331
and 3*11 = 33
one of the ages must end in 0 or 5 to get 1320 as a product
so try 10*11*12 = 1320 Well now, how do you like that ? :)
Three students came to the bake sale to shop. The sum of their ages is 33. The product of their ages is 1,320. How old are they?
5 answers
10,11, and 12
I figured that they were probably close in ages, so (age)^3 is approximately 1320
took the cuberoot of 1320 which was close to 11
sure enough 1320 divides by 11 120 time
and 120 = 10x12
and sure enough 10+11+12 = 33
I figured that they were probably close in ages, so (age)^3 is approximately 1320
took the cuberoot of 1320 which was close to 11
sure enough 1320 divides by 11 120 time
and 120 = 10x12
and sure enough 10+11+12 = 33
ain't it scary how we think alike?
LOL
LOL
That is pretty funny :)
The answer is that there ages are 10,11,12