1. The length of AC is
sqrt[(13-1)^2 + (5-0)^2]
= sqrt169 = 13
The length of AB is
sqrt[(4-1)^2 + (4-0)^2]
= sqrt(25) = 5
The difference in lengths is 8.
2. BC slope = delty/deltax
= (5-4)/(13-4) = 1/9
Three points A,B and C have coordinates (1,0),(4,4) and (13,5) respectively.
1.By how many units does the length of AC exceed the length of AB
2.What is the slope of BC
1 answer