The force on each of particle has magnitude... no kidding.
The force will be along the directions of the sides, due to symettry.
Each of the two forces on a charge is
kqq/.5^2
but we want only the compoent in the direction of the angle bisector, which is 30 deg from each side. Therefore, net force on each corner is
2kqq/.5^2 * cos30
Three particles have charges +20μC each.They are fixed at the corners of an equilateral triangle of side 0.5m .The force on each of particle has magnitude
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