Let the original numbers be
a, a+d, and a+2d
3a + 3d = 15 or a+d = 5 ----> d = 5-a
after the addition, the three numbers are:
a+1, a+d+4, and a+2d+19
they are now in GP, that is ....
(a+d+4)/(a+1) = (a+2d+19)/(a+d+4)
(a + 5-a + 4)/(a+1) = (a + 10-2a + 19)/(a + 5-a + 4)
9/(a+1) = (-a + 29)/9
81 = -a^2 + 28a + 29
a^2 - 28a + 52 = 0
(a - 26)(a - 2) = 0
a = 26 or a = 2
if a = 26, then d = 5-26 = -21
and the original 3 numbers were:
26, 5, and 16
if a = 2, then d = 5-2 = 3
and the original 3 numbers were:
2, 5, and 8
Your question was "find n", I will let you figure out what that means.
Three numbers whose sum is 15 are in a.p. if 1,4,19 be added to them respectively the resulting number are in g.p find n
6 answers
2,5,8, or 26,5,-16
Three numbers are in A.P and their sum is 15. If 1,4 and 19 are added to these numbers respectively, the resulting numbers are in G.P .Find the numbers.
how did the difference 9 come
good answer
Thank🙏💕 you
1 answer