three numbers are in the ratio 6:3:1, and the sum of these numbers is 420. If the first number is reduced by 50%, the second number is increased by 42, and the sum of the numbers remains the same, find the resulting ratio of the numbers.

Answer 1

6x+3x+x = 420
x=42

6*42/2 = 126
3*42+42 = 164
420-(126+164) = 130

126:164:130 = 61:82:65

Answer 2

I don't think this answer is correct because 3*42=126 than + 42 = 168 not 164