Three men and three women are waiting to be interviewed for jobs. If they are all selected in random order find the probability of each event. No man will be interviewed until at least two women have been interviewed.

2 answers

P(w) = 3/6
p(ww) = 3/6 * 2/5 = 1/5

so, the chance that 2 women in a row are chosen first is 1/5. That is the chance that no man will be interviewed 1st or 2nd.
1/20