Three masses are arranged in the (x,y) plane. The X and Y units are meters
4kg at (-1,5
3kg at (1,1)
5kg at (0,0)
What is the magnitude of theresulting force on the 5kg mass at the origin? The universal gravitational constant is 6.673e-11 N*m^2/kg^2. Answer in units of N.
4 answers
It is rather simple. Figure the two forces, and add as vectors.
I DID THAT BUT THE ANSWER IS WRONG. IDON'T KNOW WHY
Let me show you a shortcut:
fx= G5(4/1^1)(-1)+G5(3/1)(+1) That is the resultant fx
Fy=G5(5/5^2)(+1)+G5(3/1)(+1) that is the resultant fy
fx=G5(-1)
fy=G5(1/5+3)=G5(15/5)=5G*3
magnitude= 5G*sqrt(1+9)=5Gsqrt10
fx= G5(4/1^1)(-1)+G5(3/1)(+1) That is the resultant fx
Fy=G5(5/5^2)(+1)+G5(3/1)(+1) that is the resultant fy
fx=G5(-1)
fy=G5(1/5+3)=G5(15/5)=5G*3
magnitude= 5G*sqrt(1+9)=5Gsqrt10
If you don't understand that shortcut,don't do it.
2 answers