Asked by christina
Three integers have a sum of 7 and a product of 0. If the difference of the greatest number and the least number is 11, then the least of these numbers is?
Answers
Answered by
Marth
If they have a product of 0, then at least one of the numbers is 0.
The greatest number cannot be 0, otherwise the sum would be negative.
Now, let x = the greatest number
x - 11 = the least number
x + x - 11 + 0 = 7
2x - 11 = 7
2x = 18
x = 9
The least number is 9-11, or -2.
The greatest number cannot be 0, otherwise the sum would be negative.
Now, let x = the greatest number
x - 11 = the least number
x + x - 11 + 0 = 7
2x - 11 = 7
2x = 18
x = 9
The least number is 9-11, or -2.
Answered by
Reiny
If their product is zero, then one of them had to be a zero
so the 3 numbers can be called x,0, and y
x+y+0 = 7 or
x+y = 7 and
x-y = 11
adding them: 2x = 18
x = 9
if x=9 then y = -2
the 3 numbers are -2,0, and 9
check: is their sum = 7 ? YES
is the largest - the smallest = 11 ? YES
so the 3 numbers can be called x,0, and y
x+y+0 = 7 or
x+y = 7 and
x-y = 11
adding them: 2x = 18
x = 9
if x=9 then y = -2
the 3 numbers are -2,0, and 9
check: is their sum = 7 ? YES
is the largest - the smallest = 11 ? YES
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