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Three identical resistors are connected in series to a battery.

The voltage drop across one of the resistors is ___ times the voltage of the source.

1 answer

i the same through all
V = i Rtotal
V = i R1 + iR2 + iR3 = V1+V2+V3
R1 = R2 + R3
so V1=V2=V3
so
V = 3 V1 = 3V2=3V3
so
Vi = V/3

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