Three identical charges of 2.0 uC are placed at the vertices of an equilateral triangle, 0.15m on a side. Find the net force acting on each angle.

Answer 1

For each charge, take the vector sum of the forces due to the other two particles. Use Coulomb's law for the force due to each of the other two particles. The vector sum will be perpendicular to the opposite base. The magnitude will be 2cos30 = sqrt3 times the force due to a single particle.

F = sqrt3*k*q^2/d^2

k is the Coulomb constant
q = 2.0*10^-6 C
d = 0.15 m

Answer 2

2.7682N