in parallel: C = C1 + C2 + C3
in series: 1/C = 1/C1 + 1/C2 + 1/C3
two in parallel: 1/C = 1/(C1+C2) + 1/C3
you can see what C1,C2,C3 must be, and then get the others.
Three identical capacitors are connected so that their maximum equivalent
capacitance is 15 μF. There are three other ways to combine all three capacitors in a circuit. What is the total of the equivalent capacitances for each arrangement?
2 answers
oh yeah. There is a 3rd way:
two in series, in parallel with the third.
C = C1 + 1/(1/C2 + 1/C3)
two in series, in parallel with the third.
C = C1 + 1/(1/C2 + 1/C3)
1 answer