Three even numbers sum up to 126. The smaller is half the larger and the middle number is 3/4 the larger. What are the three numbers (list in order from smallest to largest).

Answer 1

x + y + z = 126.... equ 1

x = z/2

y = 3z/4

Put x,y into equ 1

z/2 + 3z/4 + z = 126

( 2z + 3z + 4z )/4 = 126

9z/4 =126/1

z = 56

x = 56/2 = 28

Y = 3*56/4=3*14 = 42

56 + 28 + 42 = 126

Answer 2

larger --- x
smaller = (1/2)x
middle = (3/4)x

x + x/2 + 3x/4 = 126
times 4
4x + 2x + 3x = 504
x = 56

larger is 56, smallest is 28 , middle is 42