three digit odd number divisible by 9 digits in consecutive order and digit in hundreds place is greater than the digit in the ones place?

Answer 1

to be divisible by 9 , the sum of the digits must be divisible by 9
e.g. 342 is divisible by 9 since 3+4+2=9, which is divisible by 9

I don't understand what you mean by "consecutive order", but perhaps you can take it from here with the above hint.