Three deer, A, B, and C, are grazing in a field. Deer B is located 61.0 m from deer A at an angle of 54.1 ° north of west. Deer C is located 79.8 ° north of east relative to deer A. The distance between deer B and C is 98.1 m. What is the distance between deer A and C?

Answer 1

figure the angle θ between the lines AB and BC. Then use the law of cosines to get AC.

AC^2 = 61^2 + 98.1^2 - 2(61)(98.1)cosθ

Or, you can use the law of sines twice to find angle C and then AC.