a. E = 3 * 500 = 1500 Volts.
b. Ceq = 120/3 = 40 pF.
Q = Ceq*E = 40 * 1500 = 60,000 Pico Coulombs.
c. Energy = 0.5Ceq*E^2 = 0.5*40 * 1500^2 =
Three capacitors, each of capacitance 120 pF, are each charged to 500 V and then connected in series. Determine (a) the potential difference between the end plates, (b) the charge on each capacitor, and (c) the energy stored in the system
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