ndidate was correct in their statement about the average income in Slugville?
To calculate the mean income in Slugville, we add up all the incomes and divide by the number of residents:
(0 + 0 + 0 + 0 + 0 + 0 + 0 + 0 + 200 + 200 + 200 + 200 + 200 + 200 + 200 + 30,600) / 16 = $1912.50
So, the mean income in Slugville is $1,912.50 per week.
None of the candidates were completely correct in their statement about the average income in Slugville. Mayor Elyse Phillips overstated the average income, Candidate Lily Jackson understated it, and Candidate Ronnie Ruis said there was no average income, which is incorrect.
Three candidates are running for the mayor of Slugville. Each has determined the typical income of residents of Slugville, and they use that information for campaign sound bites.
"Slugville is doing great! The average income for each person is $ 2,000 per week." said Mayor Elyse Phillips
"Slugville is nice, but it needs my help! The average income is only $ 100 per week" said Candidate Lily Jackson
"Slugville is a lot of trouble! The average income is $ 0 per week"
Said Candidate Ronnie Ruis
Some of the candidates are confused about “average.”
Slugville has only 16 residents.
Their weekly incomes are:
$0, $0, $0, $0, $0, $0,$0, $0, $200, $200, $200, $200, $200, $200, $200, and $30,600.
Calculate the mean income in Slugville. Which ca
11 answers
Calculate the mode income in Slugville. Which candidate is using the mood in their speech
Does anyone in Slugville have an income that equals the mode? Explain
Does anyone in Slugville have an income that equals the mode? Explain
To calculate the mode income in Slugville, we look for the income that appears most frequently. In this case, the income of $200 appears most frequently, occurring 8 times. Therefore, the mode income in Slugville is $200 per week.
Candidate Lily Jackson is using the mode in her speech, as she stated that the average income in Slugville is $100 per week, which is closer to the mode income of $200.
In Slugville, none of the residents have an income that equals the mode. The highest income in Slugville is $30,600, which is higher than the mode income of $200.
Candidate Lily Jackson is using the mode in her speech, as she stated that the average income in Slugville is $100 per week, which is closer to the mode income of $200.
In Slugville, none of the residents have an income that equals the mode. The highest income in Slugville is $30,600, which is higher than the mode income of $200.
1. Calculate the MAD of the incomes in slugville.
2. What does the range and MAD tell you about the variability of Slugville
2. What does the range and MAD tell you about the variability of Slugville
1. To calculate the Mean Absolute Deviation (MAD) of the incomes in Slugville, we first need to calculate the mean income, which we found earlier to be $1,912.50 per week. Then, we find the absolute difference between each income and the mean income, sum those differences, and divide by the number of observations (16):
MAD = ( |0 - 1912.50| + |0 - 1912.50| + ... + |30600 - 1912.50| ) / 16
MAD = ( 1912.50 + 1912.50 + 1912.50 + ... + 28687.50 ) / 16
MAD = 52480 / 16
MAD = 3280
Therefore, the Mean Absolute Deviation (MAD) of the incomes in Slugville is $3,280.
2. The range and MAD provide different measures of variability in the incomes of Slugville. The range is the difference between the highest and lowest incomes, which in this case is $30,600 - $0 = $30,600. The MAD, on the other hand, measures the average absolute difference of each income from the mean income, which is $3,280 in this case.
The large range of $30,600 indicates that there is a wide spread between the highest and lowest incomes in Slugville. On the other hand, the MAD of $3,280 suggests that there is a significant amount of variability or dispersion in the incomes around the mean income.
In summary, the range and MAD indicate that there is a large variability in incomes in Slugville, with some residents having very high incomes and others having much lower incomes compared to the mean income.
MAD = ( |0 - 1912.50| + |0 - 1912.50| + ... + |30600 - 1912.50| ) / 16
MAD = ( 1912.50 + 1912.50 + 1912.50 + ... + 28687.50 ) / 16
MAD = 52480 / 16
MAD = 3280
Therefore, the Mean Absolute Deviation (MAD) of the incomes in Slugville is $3,280.
2. The range and MAD provide different measures of variability in the incomes of Slugville. The range is the difference between the highest and lowest incomes, which in this case is $30,600 - $0 = $30,600. The MAD, on the other hand, measures the average absolute difference of each income from the mean income, which is $3,280 in this case.
The large range of $30,600 indicates that there is a wide spread between the highest and lowest incomes in Slugville. On the other hand, the MAD of $3,280 suggests that there is a significant amount of variability or dispersion in the incomes around the mean income.
In summary, the range and MAD indicate that there is a large variability in incomes in Slugville, with some residents having very high incomes and others having much lower incomes compared to the mean income.
put it shorter
The range of incomes in Slugville is $30,600, indicating a wide spread between the highest and lowest incomes. The Mean Absolute Deviation (MAD) of $3,280 shows significant variability around the mean income. This suggests that there is a wide range of incomes in Slugville, with some residents earning much higher or lower than the average income.
When you decide to use a measure of center--mode, median, or mean. You must choose which measure best helps you tell the story of data.
A. Which do you consider to be the typical income for a resident of Slugville. Choose either the mean, the median. or the mode.
B, Explain why you chose your answer in Part A
A. Which do you consider to be the typical income for a resident of Slugville. Choose either the mean, the median. or the mode.
B, Explain why you chose your answer in Part A
A. For determining the typical income for a resident of Slugville, I would choose the median income.
B. I chose the median income because it is less affected by extreme values or outliers in the data, such as the very high income of $30,600. By using the median, we can find the income in the middle of the data set, which would be $200. This better represents a typical income for a resident of Slugville, as it is not influenced as much by outliers. The median provides a more accurate depiction of the central tendency of the incomes in the dataset.
B. I chose the median income because it is less affected by extreme values or outliers in the data, such as the very high income of $30,600. By using the median, we can find the income in the middle of the data set, which would be $200. This better represents a typical income for a resident of Slugville, as it is not influenced as much by outliers. The median provides a more accurate depiction of the central tendency of the incomes in the dataset.
Complete the line plot to model the weekly income in slugville
-------0-------------200------------------------------------------------30,600
-------0-------------200------------------------------------------------30,600
I apologize for the limitation in my formatting. Please see below for a description of the line plot modeling the weekly income in Slugville:
Starting from the left, you would have a line representing six zeros, followed by a line at 200, and then another line at 30,600. Please note that this is a simplified representation, and the spacing between the income values may vary due to formatting constraints.
Starting from the left, you would have a line representing six zeros, followed by a line at 200, and then another line at 30,600. Please note that this is a simplified representation, and the spacing between the income values may vary due to formatting constraints.
3 answers