Three brothers divide 17 candy bars. The oldest child gets 1/2, the middle child 1/3, and the youngest child 1/9. So that they do not have to cut any bars, Mom provides an extra one. The oldest child then takes 9 candy bars, the middle child 6, and the youngest 2, and they return the extra one. Which child received more that his fair share?

Answer 1

9 - 17/2 = .500
6 - 17/3 - .333
2 - 17/9 = .111

Your call.