F accelerates the three boxes equally
since C is half of the total system mass, F equals twice the force on C
Three boxes are lined up so that they are touching each other as shown in the figure below. Box A has a mass of 30.0 kg, box B has a mass of 45.0 kg, and box C has a mass of 75.0 kg. An external force (F) pushes on box A toward the right, and the force that box B exerts on box C is 190 N.What is the acceleration of the boxes? (Express your answer to three significant figures.) What is the magnitude of the external force F (Express your answer to three significant figures.)
2 answers
Fa+b=-Fc
therefore, acceleration can be calculated by:
a=F/(mass of a+b)
External force
Fa=-Fb+c
The force of box a on boxes b+c is the external force, therefore external force = force of boxes b+c on a
Fb+c= (mass b+c)*acceleration from above
therefore, acceleration can be calculated by:
a=F/(mass of a+b)
External force
Fa=-Fb+c
The force of box a on boxes b+c is the external force, therefore external force = force of boxes b+c on a
Fb+c= (mass b+c)*acceleration from above
1 answer