work= force*displacement
since the question asks only for the work done of f1:
Work(f1)=20N*.600m
ans. 12J
Three applied forces, F1= 20.0 N, F2= 40.0 N, and F3 = 10.0 N act on an
object with a mass of 2.00 kg which can move along an inclined plane as shown in the figure. The
questions refer to the instant when the object has moved 0.600 m along the surface of the inclined
plane in the upward direction. Neglect friction and use g = 10.0 m/s
2
. What is the amount of work done
by force F1 as the object moves up the inclined plane
1 answer