x + 2x + 3x + y = 360
y + 6x = 360
x + 3x = 200
x = 50
so
y + 300 = 360
y = 60
50, 100, 150, 60
Three angles of a quadrilateral are in the ratio 1:2:3. The sum of the least and the greatest of these angles is 200°. Find all the four angles of the quadrilateral.
2 answers
x+3x=200
x=50 deg
360=sum of three + fourth
360=x+2x+3x + fourth
360=6*50+fourth
fourth= ..... degrees
x=50 deg
360=sum of three + fourth
360=x+2x+3x + fourth
360=6*50+fourth
fourth= ..... degrees