The sum of the angle measures in a triangle is always 180°. Therefore, we can write the equation:
mLACB + mBCD + mDCE = 180°
Since we are given that mDCE = 13°, the equation becomes:
(x + 15)° + (x + 48)° + 13° = 180°
Combining like terms, we have:
2x + 76 = 180
Subtracting 76 from both sides:
2x = 104
Dividing both sides by 2:
x = 52
Now we can substitute x = 52 back into the equation for mBCD:
mBCD = (x + 48)°
mBCD = (52 + 48)°
mBCD = 100°
Therefore, the measure of BCD is 100°.
Three angles measures add to 180° and have the following measures: mLACB = (x + 15) •
, m_BCD = (x + 48) • ,and mDC E = 13°
What is the measure of BCD? (1 point)
1 answer