Let's define the cost of an adult ticket as \( A \) and the cost of a child ticket as \( C \).
According to the problem:
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Three adult and three child tickets were purchased for a total of $75: \[ 3A + 3C = 75 \]
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The cost of each child ticket is $3 less than the cost of an adult ticket: \[ C = A - 3 \]
Now we can substitute \( C \) in the first equation:
\[ 3A + 3(A - 3) = 75 \]
Simplify the equation: \[ 3A + 3A - 9 = 75 \] \[ 6A - 9 = 75 \] \[ 6A = 75 + 9 \] \[ 6A = 84 \] \[ A = 14 \]
Now we can find the cost of a child ticket using the relation \( C = A - 3 \): \[ C = 14 - 3 = 11 \]
Thus, the ticket prices are:
- Adult ticket: $14
- Child ticket: $11
The correct response is: an adult ticket is $14 and a child ticket is $11.