dG = 0 = dH - TdS.
Plug in 40,700 J/mol for dH and 373 for T, solve for dS, and that's for 1 mol. Correct for 3.3 mol.
This temperature represents the freezing
point of ethanol. (Which means delta G =
0) What is the entropy change for the vaporization of 3.3 mol H2O(ℓ) at 100◦C and 1 atm?
∆H= 40700 J/mol.
Answer in units of J/K
1 answer