To find the equation of the linear function that models the relationship given in the table, we can first determine the slope (m) using the two points: (4, 38) and (6, 58).
The formula for the slope between two points \((x_1, y_1)\) and \((x_2, y_2)\) is:
\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]
Let's assign:
- \( (x_1, y_1) = (4, 38) \)
- \( (x_2, y_2) = (6, 58) \)
Now calculate the slope:
\[ m = \frac{58 - 38}{6 - 4} = \frac{20}{2} = 10 \]
Now that we have the slope \(m = 10\), we can use the point-slope form of the linear equation, which is:
\[ y - y_1 = m(x - x_1) \]
Using point \((4, 38)\):
\[ y - 38 = 10(x - 4) \]
Distribute the slope:
\[ y - 38 = 10x - 40 \]
Add 38 to both sides:
\[ y = 10x - 2 \]
Thus, the equation of the linear function that models the relationship shown in the table is:
\[ \boxed{y = 10x - 2} \]