1. When does the rock reach its maximum height?
To find the time at which the rock reaches its maximum height, we need to find the vertex of the parabolic function h(t) = -16t^2 + 50t + 20.
The formula for the x-coordinate of the vertex of a parabola in the form y = ax^2 + bx + c is given by x = -b/(2a).
In this case, a = -16 and b = 50.
Therefore, x = (-50)/(2*(-16)) = 1.563 seconds.
So, the rock reaches its maximum height at 1.563 seconds.
2. What is the maximum height it reaches?
To find the maximum height reached by the rock, we need to substitute the value of t = 1.563 into the function h(t).
h(1.563) = -16(1.563)^2 + 50(1.563) + 20 = -16(2.441769) + 78.15 + 20 = -39.068304 + 98.15 = 59.081696 inches.
Therefore, the maximum height reached by the rock is 59.08 inches.
Therefore, the correct answers are:
1. When does the rock reach its maximum height? a. 1.563 seconds
2. What is the maximum height it reaches? e. 59.08 inches
This same rock is thrown and it follows the path modeled by the function:
h (t) = -16t^2 + 50t + 20
1. When does the rock reach it's maximum height?
2. What is maximum height it reaches
a. 1.563 seconds
b. 80.89 inches
c. 130.29 inches
d. 3.45 seconds
e. 56.063 inches
f. 2.542 seconds
1 answer
3 answers