1). Put the equation in the form of
y= a(x-h)^2+k
Then the vertex will be at h,k
y=-2(x^2-x-5)=-2(x^2-x+1/4)+10+1/2
y=-2(x-1/2)^2+ 10.5
so h=1/2, k= 10.5
line of symettry is as x=h
max.min is at x=h, so max is 10.5
This Question is in multiple sections.
f(x)= -2x^2+2x+10 is the problem
1)What is the x coordinate of vertex in simplified fraction?
2)What is the y coordinate of vertex in simplified fraction?
3)What is the line of symmetry?
4)What is the maximum/minumum of f(x)?
5)The value of f(1/2)=21/2 is minimum or maximum?
Can you please explain these steps to me in detail so that I get it. I'm preparing for a final in a couple days and have a couple last minute questions about certain problems on my algebra before I do my final. Thank You!!!
2 answers
Thank you!!!! Now, can you please tell me how to choose the correct graphing without actually seeing everything right in front of you?
1 answer