This question is from my workbook (Pre-Calculus 11). Can someone please help me understand it?
Suppose theta is an angle in standard position with terminal army in quadrant III and tan theta = 6/3. Determine the exact calues of the other two primary trigonometric rations.
In quardatn III, x is ______ and y is ________ (r is always positive).
I don't understand how to draw the triangle for reference.
Any help will be greatly appreciated. Thank you.
2 answers
(-6r)-5=7-12r
tan = y/x
since both x and y are negative in QIII, then you must have
tan = 6/3 = -6/-3,
so y = -6 and x = -3
now, r = 3sqrt(5)
sin = y/r
cos = x/r
just plug and chug
since both x and y are negative in QIII, then you must have
tan = 6/3 = -6/-3,
so y = -6 and x = -3
now, r = 3sqrt(5)
sin = y/r
cos = x/r
just plug and chug
1 answer