Without a schematic, it is difficult to know your circuit configuration.
Leaving point A you go through R1, thru
parallel resistrs R1-R2, through series resistor R4 and parallel resistors R5-R6. I COUNTED 6 RES., you show only 5.
so i missed something.
this question is about resistors in parallel.
If i have a circuit, and it starts at point A with one resistor, then splits to flow to two resistors, and one of those two splits agin, to two more, then they all join again at the end at point B, what equation do I use?
is it R1+(1/R2+1/R3+1/R4+1/R5)^-1?
Or, since the second parallel is IN a parallel, do I have to do something else with the equation?
2 answers
yes you were right, I only showed 5 and the question had six. I figured it out finally. What I didn't understand was that I had to find the resistance of the first set of parallels and then ADD that to the one beside it in series, then take the parallel of that whole circuit. I'm sure this makes little to no sense, but I finally get it. Thank you for looking at my question though!