This map shows ordered pairs that belong to the function f(x)=x2

Question

. What is the missing value?
in the x map it has the numbers
-2
-1
0
1
___
in the y map it has the numbers
0
1
4
(1 point)

___

Answer 1

To find the missing value for the function \( f(x) = x^2 \), we need to evaluate \( f(x) \) for the missing \( x \) value.

The current ordered pairs based on the given function \( f(x) = x^2 \) are:

• When \( x = -2 \): \( f(-2) = (-2)^2 = 4 \)
• When \( x = -1 \): \( f(-1) = (-1)^2 = 1 \)
• When \( x = 0 \): \( f(0) = 0^2 = 0 \)
• When \( x = 1 \): \( f(1) = 1^2 = 1 \)

The missing \( x \) value corresponds to the \( y \) value that is not listed in the y map, which is \( 4 \).

Now, look at the values of \( x \) we already have:

• For \( y = 0\), \( x = 0 \)
• For \( y = 1\), \( x = -1 \) or \( x = 1 \)
• For \( y = 4\), \( x\) must be \( -2 \) or \( 2 \).

Since \( -2 \) is already in the x map, the missing \( x \) value must be \( 2 \).

Thus, the missing value in the x map is \( \boxed{2} \).