The numerator can be factored:
(x^4 - 8x^2 + 15) = (x^2 - 3)(x^2 - 5)
Use that and cancel the common (x^2 - 3) in the numerator and denominator.
this is the third and final problem I can not figure out. Help please
Divide
(x^4 - 8x^2 + 15) / (x^2 -3) =
3 answers
(x^4 - 8x^2 + 15) = (x^2-3)(x^2-5)
so there will be a (x^2-3) term in the numerator and denominator that will cancel leaving (x^2-5)
so there will be a (x^2-3) term in the numerator and denominator that will cancel leaving (x^2-5)
on bady