This is part of the indices section, how do you work it out please:

Question

(8/27) to the power of 2/3

Answer 1

The trick is to recognize that 8 and 27 are cubes of 2 and 3, respectively. So take the cube roots first, as follows

(8/27)^(2/3) = [(8/27)^(1/3)]^2
= (2/3)^2 = 4/9