The correct answer is D. 12 Newtons.
To find the net force, we need to consider both the magnitude and direction of the forces. In this case, the 6 N force pointing left and the 2 N and 4 N forces pointing right are in opposite directions. To find the net force, we subtract the forces pointing right from the force pointing left:
6 N (left) - 2 N (right) - 4 N (right) = 6 N - 6 N = 0 N
Therefore, the net force acting on the box is 0 Newtons.
This is a vector diagram of the forces acting on the box.
A vector diagram.Short description, A vector diagram.,Long description,
On one side of a box, a vector with force 6 N points left with a very long arrow. On the opposite side of the box, a vector with force 2 N, with a very short arrow, and a vector with force 4 N, with a medium arrow, point right.
Question
What is the magnitude of the net force acting on the box?
Answer options with 4 options
A.
0 Newtons
B.
2 Newtons
C.
6 Newtons
D.
12 Newtons
1 answer