Question

This is a two-dimensional kinematics question:

A particle's position coordinates (x,y) are (2m, 3m) at t=0; (6m, 7m) at t=2s, and (13m, 14m) at t=5s. Find the average velocity vector between t=0s and a) t=2s, b) t=5s.

I don't know how to find this without acceleration being given.

Answer 1

You don't need to know the acceleration.

For average velocity, just divide the position change vector by the time interval.

Between t= 0 and 2s, the x position increases by 4 m and the y position increases by 4 m.

The average velocity components are
Vx = 2 and Vy = 2.

Do the 5 second case the same way.