This is a Pythagorean Theorem
x^2 + (2x + 4)^2 = (2x + 6)^2
4 answers
no
so what are we doing with it?
Solving it ?
x^2 + 4x^2 + 16x + 16 = 4x^2+ 24x + 36
x^2 -8x -20 = 0
(x-10)(x+2) = 0
x = 10 or x = -2
but if x, 2x+4, and 2x+6 are the sides, then x = -2 makes no sense
so x = 10
check
sides would be 10, 24, and 26
which is twice the sides of the 5,12, 13 right-angled triangle, which I recognize to be right-angled.
So my answer is correct.
Solving it ?
x^2 + 4x^2 + 16x + 16 = 4x^2+ 24x + 36
x^2 -8x -20 = 0
(x-10)(x+2) = 0
x = 10 or x = -2
but if x, 2x+4, and 2x+6 are the sides, then x = -2 makes no sense
so x = 10
check
sides would be 10, 24, and 26
which is twice the sides of the 5,12, 13 right-angled triangle, which I recognize to be right-angled.
So my answer is correct.
I was not asking if it was a Pythagorean Theorem? This is the equation that I have to solve
Thank you
1 answer