This is a homework question and I have no idea what I'm doing wrong.

Question

A heavy sled is being pulled by two people as shown in the figure. The coefficient of static friction between the sled and the ground is ìs = 0.611, and the kinetic friction coefficient is ìk = 0.467. The combined mass of the sled and its load is m = 276 kg. The ropes are separated by an angle ö = 27°, and they make an angle è = 31.4° with the horizontal. Assuming both ropes pull equally hard, what is the minimum rope tension required to get the sled moving? If this rope tension is maintained after the sled starts moving, what is the sled\'s acceleration?

I've solved for N=mg and friction=Nu static. N-friction=horizontal component, and then T=horizontal component/cos(31.4). After I get this, using T-(Tu kinetic) to solve for a=T/m. This is an online question and it keeps saying both are wrong, need help please so I can understand how to do this.

I've solved for N=mg and friction=Nu static.  N-friction=horizontal component, and then T=horizontal component/cos(31.4).  After I get this, using T-(Tu kinetic) to solve for a=T/m. This is an online question and it keeps saying both are wrong, need help please so I can understand how to do this.