To determine if the system of inequalities \( y \geq x - 2 \) and \( y < 32 - 10 \) has solutions, we first analyze each inequality.
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Inequality 1: \( y \geq x - 2 \)
- This is a linear inequality representing the region above (and including) the line \( y = x - 2 \).
- The line itself has a y-intercept at \(-2\) and a slope of \(1\).
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Inequality 2: \( y < 32 - 10 \)
- Simplifying gives \( y < 22 \).
- This represents the region below the horizontal line \( y = 22 \).
Next, we look for the intersection of these two regions.
- The first inequality includes the area above the line \( y = x - 2 \), while the second inequality restricts the solutions to below the line \( y = 22 \).
To check if the system has solutions, we can find where these two lines intersect:
Set \( x - 2 = 22 \): \[ x - 2 = 22 \implies x = 24 \]
At \( x = 24 \), we find: \[ y = x - 2 \implies y = 24 - 2 = 22 \]
So the lines intersect at the point \( (24, 22) \).
Now we can interpret the system of inequalities:
- The region defined by \( y \geq x - 2 \) is above the line (inclusive).
- The region defined by \( y < 22 \) is below the line (not inclusive).
Thus, the solutions to the system will be the region where \( y \) is at least \( x - 2 \) while also being less than \( 22 \).
Conclusion:
Yes, the system of inequalities has solutions. The solution region is above the line \( y = x - 2 \) and below the line \( y < 22 \). The valid region is bounded by these two lines.