To determine which labeled point is a viable solution for the inequality \( 25x + 15y \geq 200 \), we can replace \( x \) and \( y \) in each point with the respective coordinates and check if they satisfy the inequality.
- Identify the coordinates of each labeled point on the graph.
- For each point, substitute the \( x \) and \( y \) values into the inequality \( 25x + 15y \).
- Check if the result is greater than or equal to 200.
Here are hypothetical examples of points for demonstration:
- Point A: \( (4, 5) \)
- Point B: \( (2, 8) \)
- Point C: \( (6, 0) \)
- Point D: \( (0, 10) \)
Let's calculate for each example:
-
Point A: \( 25(4) + 15(5) = 100 + 75 = 175 \) (not valid since \( 175 < 200 \))
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Point B: \( 25(2) + 15(8) = 50 + 120 = 170 \) (not valid since \( 170 < 200 \))
-
Point C: \( 25(6) + 15(0) = 150 + 0 = 150 \) (not valid since \( 150 < 200 \))
-
Point D: \( 25(0) + 15(10) = 0 + 150 = 150 \) (not valid since \( 150 < 200 \))
You will need to plug in the actual coordinates of the labeled points from your graph to find out which point satisfies the inequality \( 25x + 15y \geq 200 \). If a point yields a result that is 200 or greater, then it is a viable solution within the context of Lina's earnings.
If you have specific labeled points, please provide them for precise calculations.
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