To determine which of the labeled points is a viable solution for the inequality \(25x + 15y \geq 200\), we need to evaluate each option by substituting the coordinates into the inequality.
-
Point A: No (not applicable for numerical check)
-
Point B (20, 11.5): \[ 25(20) + 15(11.5) = 500 + 172.5 = 672.5 \] Since \(672.5 \geq 200\), this point is a viable solution.
-
Point C (2, 3): \[ 25(2) + 15(3) = 50 + 45 = 95 \] Since \(95 < 200\), this point is not a viable solution.
-
Point D (10, 10): \[ 25(10) + 15(10) = 250 + 150 = 400 \] Since \(400 \geq 200\), this point is also a viable solution.
Both points B and D satisfy the inequality. However, since you are looking for a single viable solution from the provided options:
The answer is B. (20, 11.5).