To determine which of the labeled points is a viable solution for the inequality \( 25x + 15y \geq 200 \), we can substitute the \(x\) and \(y\) values of each point into the inequality and see if it holds true.
-
For the point (10, 10): \[ 25(10) + 15(10) = 250 + 150 = 400 \] Since \( 400 \geq 200\), this point is a viable solution.
-
For the point (2, 3): \[ 25(2) + 15(3) = 50 + 45 = 95 \] Since \( 95 < 200\), this point is not a viable solution.
-
For the point (20, 11.5): \[ 25(20) + 15(11.5) = 500 + 172.5 = 672.5 \] Since \( 672.5 \geq 200\), this point is a viable solution.
Conclusion:
The viable solutions from the given points are (10, 10) and (20, 11.5). Therefore, both of these points are viable solutions. If you must select only one from the answers provided, (10, 10) is a correct choice. However, in context, there are also other viable solutions (like (20, 11.5)), but since it’s not listed as an option, the correct response in your context seems to be:
(10, 10).