To determine if the chemical reaction \( \text{SnO}_2 + \text{H}_2 \rightarrow \text{Sn} + \text{H}_2\text{O} \) is balanced, we need to compare the number of each type of atom on both sides of the equation.
Reactants:
-
SnO\(_2\) has:
- 1 Sn (tin)
- 2 O (oxygen)
-
H\(_2\) has:
- 2 H (hydrogen)
Total in Reactants:
- 1 Sn
- 2 O
- 2 H
Products:
-
Sn has:
- 1 Sn
-
H\(_2\)O has:
- 2 H
- 1 O
Total in Products:
- 1 Sn
- 1 O
- 2 H
Now, let's compare both sides:
Reactants:
- Sn: 1
- O: 2
- H: 2
Products:
- Sn: 1
- O: 1
- H: 2
Overall, the reaction is:
- Tin (Sn): 1 = 1
- Oxygen (O): 2 ≠ 1 (unbalanced)
- Hydrogen (H): 2 = 2
Since the number of oxygen atoms does not match (2 in reactants and 1 in products), the reaction is unbalanced.
To balance it, you could adjust the coefficients in front of the compounds. For example, placing a coefficient of 2 in front of H\(_2\)O would balance the oxygen atoms:
2 SnO\(_2\) + 4 H\(_2\) → 2 Sn + 4 H\(_2\)O
This way you will have matches for all elements on both sides of the reaction.