third term using the recursive rule f(1)=.2

Question

for f(n)=2f(n-1)/5 + 1

Answer 1

just keep working at it ...

f(1) = .2
f(2) = 2f(1)/5 + 1
= 2(.2)/5 + 1
= 1.08

f(3) = 2f(2)/5 + 1
= 2(1.08)/5 + 1
= 1.432